Joel Edgerton (Warrior) is setting his sights west as he is in negotiations to join Jane Got a Gun, a Western directed by Lynne Ramsay (We Need to Talk About Kevin). Written by Brian Duffield, Jane Got a Gun centers on the titular good girl married to a very bad man who turns against his outlaw gang and gets a back full of bullets for his trouble. With the outlaws still out for revenge, Jane is forced to turn to an old flame in order to bring justice to the deadly gunslingers. Natalie Portman (Black Swan) is set to star in the lead with Michael Fassbender (Prometheus) playing the ex-lover. Edgerton is in negotiations to play the outlaw husband. Jane Got a Gun is set to begin production in February. Hit the jump for more.
Deadline reports that Edgerton is in talks to join Jane Got a Gun as Jane’s renegade husband, Bill Hammond. Edgerton can next be seen in Kathryn Bigelow’s Zero Dark Thirty and was reported as being on the short list for the lead in James Gunn’s Guardians of the Galaxy.
Here’s the synopsis for Jane Got a Gun:
Young and pretty with a soul of pure steel, Jane Hammond (Natalie Portman) is a good girl married to one of the worst baddies in town. When her husband Bill turns against his own gang, the vicious Bishop Boys, and returns home barely alive with eight bullets in his back, Jane knows it’s time to ditch the dress for a pair of pants and strap on her own gun. As the relentless leader John Bishop gears up for revenge, Jane’s best hope for her family’s survival rests with her old love Dan Frost (Michael Fassbender) – a gunslinger whose hatred for Bill is only slightly overshadowed by his love for Jane. Together Jane and Dan spring clever traps, luring Bishop’s men to certain death just as their old feelings for each other resurface amidst the flying bullets.
With director Lynne Ramsay (WE NEED TO TALK ABOUT KEVIN, MORVERN CALLAR) at the helm, the rich dimensions of these characters find their best ally with Jane out in front, taking her fate into her own hands with the kind of bravado legends are made of.